Jane, looking for Tarzan, is running at top speed (5.9 m/s) and grabs a vine hanging vertically from a tall tr

Jane, looking for Tarzan, is running at top speed (5.9 m/s) and grabs a vine hanging vertically from a tall tree in the jungle. How high can she swing upward?

Jane, looking for Tarzan, is running at top speed (5.9 m/s) and grabs a vine hanging vertically from a tall tr
hard
Reply:This is about converrting KE to PE, i.e

.5mv^2 =mgh, Canceling and cross multiplying

h=.5v^2/g

=.5*(5.9^2)/9.8

=1.8m